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Magnetic Launcher

  1. May 2, 2015 #1
    1. The problem statement, all variables and given/known data

    HW13_4.jpg A sort of 'projectile launcher' is shown in the figure above. A large current moves in a closed loop composed of fixed conducting rails, a power supply, and a very light, almost frictionless metal bar touching the rails. A magnetic field is perpendicular to the plane of the circuit. If the bar has length L = 15.5 cm, mass m = 1.44 g, and is placed in a field of 1.96 T, what constant current flow is needed in order for it to accelerate to 30 m/s in a distance of 1.0 m?

    •Start by finding the magnetic force on the bar, which determines its acceleration via Newton's second law F = ma.
    •The kinematic relation v2 = 2ax may be helpful (where v is the velocity attained by an object having acceleration a over a distance x.)

    2. Relevant equations

    F = I*B*L (current, magnetic field, length)

    F = m*a

    v^2 = 2ax where v is the velocity of object with an acceleration of a/x and x being the distnace

    3. The attempt at a solution

    F = I*B*L
    43.2 = I*(1.96T)(15.5*10^-2cm)
    I tried solving for I that way, which didn't work

    I tried the velocity using the v^2 = 2ax equation that was given and I got 7.746

    But I'm not quite sure what to do with this.
     
  2. jcsd
  3. May 2, 2015 #2

    mfb

    User Avatar
    2016 Award

    Staff: Mentor

    Where does the value 43.2 come from? You need the kinematics to find F.
    7.746 what? And how did you get it?
     
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