- #1
Angie K.
- 108
- 1
Homework Statement
A straight 2.34-mm-diameter copper wire can just 'float' horizontally in air because of the force of the Earth's magnetic field B, which is horizontal, perpendicular to the wire, and of magnitude 5 × 10-5 T. What current I does the wire carry? (The density of copper is 8.96 g/cm3).
•The wire feels a downward gravitational force of magnitude mg, where m is mass and g = 9.80 m/s2 is the gravitational field strength near the Earth's surface.
Homework Equations
F = I*L*B sin θ
The Attempt at a Solution
[/B]
F = I*L*B
F = mg = mass of copper * Earth's gravitational field strength
(63.546*9.8) = I*(.234)(5*10^-5)
then solve for I
but I think I'm doing something wrong with the F (plugging in wrong values?)