1. The problem statement, all variables and given/known data Three long parallel wires are a distance L = 5.71 cm from one another. (Looking at them, they are at three corners of an equilateral triangle.) The top wire has a diameter of 1.8 mm and is made of copper; it is suspended in air due to the magnetic forces from the bottom two wires. The current in each of the bottom two wires is I0 = 2.08 A into the page. Calculate the magnitude of the required current I in the suspended wire. (The density of copper is 8.96 g/cm3.) 2. Relevant equations Force per length F/L= (μ0/2Π)*(I1*I2/d) Magnetic Force FB = I*L*B Magnetic Field B=μ0/2Π*I/r, OR B= 2Πx10-7(I/d) 3. The attempt at a solution I know that the Fg will have to equal the Fb to keep the wire suspended. First, I found the mass of the wire by using the density, D=M/V DV=M D*A*L=M (8.96E3kg)/m3(Π*.001882m)*L=m .0995kg/m*L=m Then I can find Fg, so Fg=mg Fg = (.0995kg/m*L)(9.80m/s)= .975kg/s*L Then FB = I*L*B is equal to Fg, but first I need to find the magnetic field. B = 2Πx10-7(2.08/.0571)*2 = 4.58*10-5kg/A*s I multiplied by two beacause the magnetic fields add up, since both fields are going clockwise. So now FB=Fg .975kg*L = I*L(4.58*10-5kg/A*s) Solving for I, I get 2.13*104A, even before I check the answer I know that it's wrong because it's a ridiculously large number. Please help me, I'm not sure where I went wrong.