1. Aug 16, 2010

### shiu1

1. The problem statement, all variables and given/known data

the charge of Q= 1.6 uC is moving along the line x=y with speed v= 4.0*10^5 m/s. What is the vecotr force it experiences due to the magnetic field B= Boz, where Bo = 0.25T?

2. Relevant equations

3. The attempt at a solution

i know Fb must be perpendicular to B and B is on the z axis. but i don't know what should i do afterwards. please help.

2. Aug 16, 2010

### N-Gin

You just need to use the Lorentz force.

$$\vec{F}=q(\vec{E}+\vec{v}\times\vec{B})$$

Remember, $\vec{E}$ and $\vec{B}$ are the fields not produced by charge $q$.