Magnetic Quantum No: Angular Momentum, Electron Orbit Orientation

In summary, when the magnetic quantum number is zero, the component of angular momentum along the magnetic field direction will also be zero. This means that the vector will have a planar configuration and its possible directions will have the common characteristic of having a zero z-component. This does not necessarily imply that the vector will be zero in a deterministic sense, but rather in a statistical sense. Therefore, if a quantum state has an associated eigenvalue of zero, it can be concluded that the angular momentum in the z-direction for that state will also be zero, indicating a global spatial feature of the state. However, this does not necessarily mean that the state will have a planar vector.
  • #1
mkbh_10
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If magnetic quantum no. is zero then component of angular momentum along magnetic field direction will be zero , what does it mean ? What can be said about the orientation of the electron orbit in this case ?
 
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  • #2
Look at the geometry of the s-orbital. What does it look like?

Zz.
 
  • #3
Suppose the magnetic field is along the z-direction (which is what we usually assume). If the z-component of a vector (any vector, not just the angular momentum vector) is zero, what are the possible directions of that vector? What characteristic do all those directions have in common?
 
  • #4
jtbell said:
Suppose the magnetic field is along the z-direction (which is what we usually assume). If the z-component of a vector (any vector, not just the angular momentum vector) is zero, what are the possible directions of that vector? What characteristic do all those directions have in common?

Ok, then we have the planar configuration for the referred vector. But one thing is m = 0 imply deterministically the Lz to be zero. Another thing is to have m = 0 as an implication of Lz to be ZERO in some statistical sense, i.e. in average. As in the first answer, the s orbital (spherical) has zero Lz, but just when done the average.

Thus, if a quantum state has an associated eigenvalue m = 0, we may conclude that Lz aplied on this state yield eigenvalue zero, which has to do with spatially global feature of the state.


In conclusion, I think that the picture of a planar vector must not correspond to quantum states with m = 0.

Best wishes

DaTario
 
Last edited:

1. What is magnetic quantum number?

The magnetic quantum number is a quantum number that describes the orientation of an electron's orbit around the nucleus. It specifies the number of orbitals in each energy level and determines the shape of the electron's orbital.

2. How is magnetic quantum number related to angular momentum?

The magnetic quantum number is related to angular momentum as it represents the magnitude of the electron's orbital angular momentum. It determines the direction in which the electron is orbiting the nucleus, and is one of the four quantum numbers used to describe an electron's state in an atom.

3. What values can the magnetic quantum number have?

The magnetic quantum number can have integer values ranging from -l to +l, where l is the azimuthal quantum number. This means that it can have values of 0, ±1, ±2, ±3, and so on.

4. How does the magnetic quantum number affect the energy of an electron?

The energy of an electron is affected by the magnetic quantum number as it determines the number of orbitals available in each energy level. This, in turn, affects the energy of the electron as different orbitals have different energy levels.

5. Can the magnetic quantum number change?

Yes, the magnetic quantum number can change as the electron moves between different orbitals in an atom. However, it can only change by ±1, as this represents the change in the direction of the electron's orbit around the nucleus.

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