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A singly charged positive ion has a mass of 2.50 X 10 ^-26 kg. After being accelerated through a potential difference of 250 V, the ion enters a magnetic field of 0.500 T, in a direction perpendicular to the field. Calculate the radius of the path of the ion in the field.

I believe the formula to use is this: r = mv/qB

and it should look like this with what is given:

r = (2.5 X 10^-26 kg) v / (1.6 X 10^-19)(.50T)

if that is correct, the only thing I'm having trouble with is the velocity. How do I find the velocity?

if that isn't correct, then I'm lost.

Thank you for your help.

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# Homework Help: Magnetics and velocity

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