What speed would a proton need to achieve
in order to circle Earth 1670 km above the
magnetic equator, where the Earth’s mag-
netic field is directed on a line between mag-
netic north and south and has an intensity of
4.1 × 10−8 T?
The mass of a proton is 1.673 × 10−27 kg.
Answer in units of m/s.
f3=Gm(proton)m(earth)/(d+R)^2 where d is 1670 km, and R is Earth distance
The Attempt at a Solution
I tried doing f1+f2=f3, b ut im not sure if this is right and i dont know how to solve for v