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## Homework Statement

What speed would a proton need to achieve

in order to circle Earth 1670 km above the

magnetic equator, where the Earth’s mag-

netic field is directed on a line between mag-

netic north and south and has an intensity of

4.1 × 10−8 T?

The mass of a proton is 1.673 × 10−27 kg.

Answer in units of m/s.

## Homework Equations

f1=qvbsin(theta)

f2=mv^2/(d+R)

f3=Gm(proton)m(earth)/(d+R)^2 where d is 1670 km, and R is Earth distance

## The Attempt at a Solution

I tried doing f1+f2=f3, b ut im not sure if this is right and i dont know how to solve for v