(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

What speed would a proton need to achieve

in order to circle Earth 1670 km above the

magnetic equator, where the Earth’s mag-

netic field is directed on a line between mag-

netic north and south and has an intensity of

4.1 × 10−8 T?

The mass of a proton is 1.673 × 10−27 kg.

Answer in units of m/s.

2. Relevant equations

f1=qvbsin(theta)

f2=mv^2/(d+R)

f3=Gm(proton)m(earth)/(d+R)^2 where d is 1670 km, and R is Earth distance

3. The attempt at a solution

I tried doing f1+f2=f3, b ut im not sure if this is right and i dont know how to solve for v

**Physics Forums | Science Articles, Homework Help, Discussion**

Dismiss Notice

Join Physics Forums Today!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

# Homework Help: Magnetism question 2

**Physics Forums | Science Articles, Homework Help, Discussion**