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silentcoder
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Homework Statement
1. Determine the magnetic force acting on an proton (m = 1.67 x 10-27 kg) moving at 2.9 x 106 m/s in a magnetic field of 6.8 T. The proton is moving south. The magnetic field points straight down.
2. A 6.0 m long wire with 7.0A of current flowing through it experiences a force of 12 N. Determine the magnitude of the magnetic field. You may assume that the current and the magnetic field are 90° to one another.
Homework Equations
1. Fm = qvbsinƟ
2. Fm = IlBsinƟ
The Attempt at a Solution
1. There was no charge given so is it alright to use charge of 1.6x10^-19?
Fm = qvbsinƟ
Fm = (1.6x10^-19 C)(2.9x10^6 m/s)(6.8T) sin 90
Fm = 2.53 x 10^-12 N
2. No magnetic field strength is given so how can i figure out the magnetic field strength?
Thanks