1. The problem statement, all variables and given/known data A long copper rod of radius R has uniformly distributed free current I. Find the value of H inside and outside the rod 2. Relevant equations ∫Hdl=I(free enclosed) 3. The attempt at a solution Copper is diamagnetic so the magnetization will be circumferential and opposite of B, producing a downwards bound current inside and an upwards bound current on the surface. We can use ampere's law to calculate H: ∫Hdl=I(free enclosed). The path dl is the amperian loop inside, with s<R, so H(2πs)= I(free enclosed) How do I find I(free enclosed)? Isn't it just I? Thanks! If the explanation could be as explicit as possible, that would be great.