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Magnitude and direction of change in velocity. Dont know how to get direction.

  1. Sep 15, 2008 #1
    1. The problem statement, all variables and given/known data

    [​IMG]

    2. Relevant equations

    I used:

    square root of: 196^2+236^2-2(196)(236)cos(45)

    to get the change in velocity of 169.4

    and then did 169.4/5 hours to get the average acceleration of 33.9

    3. The attempt at a solution

    i don't know what to do for the second one
     
  2. jcsd
  3. Sep 15, 2008 #2
    anyone? please? pretty please?
     
  4. Sep 16, 2008 #3
    wow no one knows? amazing...
     
  5. Sep 16, 2008 #4
    problem solved. thanks for the help guys...
     
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