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Magnitude and Direction

  1. Sep 17, 2008 #1
    [​IMG]

    Well I really have no idea where to begin with this one, if anyone could get me pointed in the right direction that would be much appreciated.
     
  2. jcsd
  3. Sep 17, 2008 #2
    Start out by finding the x and y components of the two vectors shown.
     
  4. Sep 17, 2008 #3
    F1 = 120cos(60*) = 60
    120sin(60*) = 103.9
    x and y = (60,103.9)

    F2 = -75cos(75*) or is it -75cos(15*)? = -19 or -72.4
    75sin(75*) or 75sin(15*) = 72.4 or 19
    x and y = (-19,72.4) or is is it (-72.4, 19)
     
  5. Sep 17, 2008 #4
    Either angle (75* or 15*) would work, the problem arises when you apply the trig functions to find the components. For example, look at how the the cosine function is defined: cos(theta) = adj/hyp. In your second answer for the x component of F2, you are saying that the leg adjacent to the angle is on the x axis, when in reality it is along the y axis according to the definition of cosine.
     
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