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## Main Question or Discussion Point

The base of a solid is a circle of radius a, and its vertical cross sections are equilateral triangles. Find the radius of the circle if the volume of the solid is 10 cubic meters.

Eq. Triangle: A = [sqrt(3)/4]s^2

V = [sqrt(3)/4]*Integral{-a to a} 4(a^2 - x^2) dx

V = 2* [sqrt(3)*Integral{0 to a} (a^2 - x^2) ]dx

What next?

(Do I use x^2+y^2=a^2 somewhere?)

Eq. Triangle: A = [sqrt(3)/4]s^2

V = [sqrt(3)/4]*Integral{-a to a} 4(a^2 - x^2) dx

V = 2* [sqrt(3)*Integral{0 to a} (a^2 - x^2) ]dx

What next?

(Do I use x^2+y^2=a^2 somewhere?)