Magnitude of acceleration

  • Thread starter osamie
  • Start date
  • #1
1
0

Homework Statement


An object moving along a straight line, at constant acceleration covers two equal, consecutive, 13 m long segments, the first one in t 1 = 1.2 s and the second one in t 2 = 2.2 s . What was the magnitude of acceleration? (in m/s2) ,
And what is the speed of the object (m/s) at the beginning of the first segment?



Homework Equations


V=(D/T)
if D/2 at V1, D/2 at V2, then
Vav = (2V1.V2)/V1+V2
acceleration = velocity/time


The Attempt at a Solution


V1 = 13/1.2 = 10.83 m/s
V2 = 13/2.2 = 5.91m/s
Vav = (2x10.83 x 5.91)/10.83 + 5.91 = 7.6
acceleration = 7.6 / 3.4
= 2.24 m/s2
 

Answers and Replies

  • #2
4
0
i have a similar problem...anyone help?
 

Related Threads on Magnitude of acceleration

  • Last Post
Replies
1
Views
470
  • Last Post
Replies
2
Views
4K
F
  • Last Post
Replies
4
Views
2K
  • Last Post
Replies
5
Views
2K
  • Last Post
Replies
1
Views
2K
  • Last Post
Replies
3
Views
6K
  • Last Post
Replies
3
Views
2K
  • Last Post
Replies
2
Views
1K
  • Last Post
Replies
4
Views
2K
  • Last Post
Replies
2
Views
8K
Top