First, use the formula d=vt to find the distance he travels before applying the brakes. Subtract that distance from 210 m. Then, use the formula:runner1738 said:An engineer in a locomotive sees a car stuck on the track at a railroad crossing in front of the train. When the engineer first sees teh car, the locomotive is 210 m from the crossing and its speed is 10 m/s. If the engineer's reaction time is .22 s, what should be the magnitude of the minmum deceleration to avoid an accident? Answer in units of m/s^2
You got the first part (the 207.8m) right. As for the rest, you canot use 22s and the time, since you don't know the time it will take hime to stop. (Sorry, I gave you the wrong formula).runner1738 said:210-2.2=d=207.8=10(22)+1/2(a)(22)^2 ? ? or is 21.78 for time?
runner1738 said:210-2.2=d=207.8=10(22)+1/2(a)(22)^2 ? ? or is 21.78 for time?
The magnitude of deceleration is a measure of how quickly an object slows down. It is usually expressed in meters per second squared (m/s²) or feet per second squared (ft/s²).
The magnitude of deceleration can be calculated by dividing the change in velocity by the time it took for the object to decelerate. The formula for calculating magnitude of deceleration is a = (vf - vi) / t, where a is acceleration, vf is final velocity, vi is initial velocity, and t is time.
The unit of measurement for magnitude of deceleration is meters per second squared (m/s²) or feet per second squared (ft/s²). This unit represents the change in velocity per unit of time.
The magnitude of deceleration is directly proportional to the amount of force acting on an object. This means that a greater magnitude of deceleration will cause an object to slow down faster, while a smaller magnitude of deceleration will cause a slower decrease in speed.
The magnitude of deceleration can be affected by various factors such as the mass and speed of the object, the surface it is decelerating on, and the presence of any external forces like friction or air resistance.