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Magnitude of electric field.

  1. Jan 22, 2008 #1
    [SOLVED] magnitude of electric field.

    1. The problem statement, all variables and given/known data

    The inner and outer surfaces of a cell membrane carry a negative and positive charge, respectively. Because of these charges, a potential difference of about 0.060 V exists across the membrane.

    The thickness of the membrane is 9.00 x 10^-9 m. What is the magnitude of the electric field in the membrane?
    in V/m

    i believe the equation to be: E = V/r

    not sure why .060 / 9.00 x 10^-9 would not work???

    2. Relevant equations

    3. The attempt at a solution

    it says my answer of: 6.7E-6 is incorrect??
  2. jcsd
  3. Jan 22, 2008 #2


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    You are dividing a number by a VERY small number. This means that your answer should be a very big number. 6.7E-6 is not very big. Check your math. I think you may have made an sign error with your exponent.
  4. Jan 22, 2008 #3
    Okay thanks, 6.7E6
  5. Jan 22, 2008 #4


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