Magnitude of force on a charge

  • #1

Homework Statement


Trying to find the magnitude of the resulting force on the -7 nC charge at the origin and my answers arent matching up. Is there a step I am missing? I used the pythagorean to find r for both ΔOrigin-Q1 and ΔOrigin-Q2. Here is the graph: http://imgur.com/90TQmQU.


Homework Equations


I've been using
Fy = kQ1Qy/r^2
Fx = kQ1Qx/r^2
Fnet = √(Fx)^2 + (Fy)^2


The Attempt at a Solution


The current attempts have landed me at
Fy = 1.736 * 10^-2
Fx = 1.481 * 10^-2
Fnet = .23 N
 

Answers and Replies

  • #2
gneill
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You'll have to show how you arrived at your results. They don't look right. Consider that the charges have values in the nanocoulomb range, and the distances are in meters. The resulting forces should be much smaller than you've found.

If you show your work, we can see how to help.
 
  • #3
Thanks for you reply. Here is what gave me those results:

Fy = ((8.99*10^9)(-7*10^-6)(8*10^-6))/5.385^2
Fx = ((8.99*10^9)(-7*10^-6)(4*10^-6))/4.123^2
Fnet = sqrt((1.736*10^-2)^2 + (1.481*10^-2)^2 ) = 0.23 N
 
  • #4
gneill
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Thanks for you reply. Here is what gave me those results:

Fy = ((8.99*10^9)(-7*10^-6)(8*10^-6))/5.385^2
Fx = ((8.99*10^9)(-7*10^-6)(4*10^-6))/4.123^2
Fnet = sqrt((1.736*10^-2)^2 + (1.481*10^-2)^2 ) = 0.23 N

Ah. You've taken the individual forces and called them Fx and Fy, but that is not the case. Each of those two forces has X and Y components which contribute to the total X and Y force components.

You would have been correct if the 8nC charge was situated on the Y-axis and the 4nC charge on the X-axis. But both are located off-axis and must therefore their locations are vectors with both x and y components. You'll need to sort out the force components of each with a bit of trig.

Also, nano is smaller than micro... micro is 10-6, nano 10-9. So adjust your charge magnitudes.
 
  • #5
Thank you for the reply. So to find the X and Y vectors of the individual charges I need to find theta and multiply each magnitude by its respective sin/cos?
 
  • #6
gneill
Mentor
20,925
2,866
Thank you for the reply. So to find the X and Y vectors of the individual charges I need to find theta and multiply each magnitude by its respective sin/cos?

That's the idea unless you are familiar with vector algebra, in which case you might forgo the trig and work directly with vector operations.
 

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