Calculating Magnitude of Forces Between Protons

[rayhan619]

Homework Statement

Two protons are 4.0 fm apart. ( 1 fm= 1 femtometer = 1*10^-15m)
a)What is the magnitude of the electric force on one proton due to the other proton?
b)What is the magnitude of the gravitational force on one proton due to the other proton?
c)What is the ratio of the electric force to the gravitational force?

Homework Equations

F = Kq1q2/r^2

The Attempt at a Solution

I figured out the 1st part. F = 14 N

but how do i start the 2nd part?

 

[LowlyPion]

b)
http://hyperphysics.phy-astr.gsu.edu/hbase/grav.html#grav

 

[nlightner]

To calculate the magnitude of the gravitational force between two protons, we can use the equation F = Gm1m2/r^2, where G is the gravitational constant (6.67*10^-11 N*m^2/kg^2), m1 and m2 are the masses of the two protons (both are equal to the mass of a proton, which is approximately 1.67*10^-27 kg), and r is the distance between them (4.0 fm = 4.0*10^-15 m). Plugging these values into the equation, we get F = 2.4*10^-24 N.

To find the ratio of the electric force to the gravitational force, we can divide the magnitude of the electric force by the magnitude of the gravitational force. In this case, the ratio is 14/2.4*10^-24, which is approximately 5.8*10^24. This means that the electric force is much stronger than the gravitational force between the two protons. This is due to the fact that the electric force is directly proportional to the product of the charges (q1 and q2), while the gravitational force is directly proportional to the product of the masses (m1 and m2). Since the charges of the protons are much larger than their masses, the electric force is significantly stronger.