I'm getting very close, but not quite close enough on this problem: A baseball is struck by a bat such that it makes an angle of 41 degrees form the direction between the batter and the pitcher. The pitch was thrown at 37.995 m/s. The ball was hit with a speed of 6.258 m/s. What was the magnitude of the impulse in kg*m/s to two sig figs? The baseball has a mass of 0.147 kg. (I take it to mean the baseball leaves the bat 41 degrees off a line drawn from the pitcher to the batter.) 1) I know that the impulse is equal to the change in momentum. So I said the change in momentum was: mballvball + (-vbat)mball = 4.6651 2) I believed that that gave me the impulse of the ball if it went straight back so I said: 4.6651/cos41 to find the hypotenuse of that x comp I had. The answer is 6.3 kg*m/s and I get 6.2 kg*m/s. I did the same problem with different numbers and while their answer was 6.9 mine was 6.0. What am I doing wrong?