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Magnitude of the pulling force

  1. Dec 1, 2007 #1
    1. The problem statement, all variables and given/known data

    A husband and wife take turns pulling their child in a wagon along a horizontal sidewalk. Each exerts a constant force and pulls the wagon through the same displacement. They do the same amount of work, but the husband's pulling force is directed 58° above the horizontal, while the wife's pulling force is directed 34° above the horizontal. The husband pills with a force whose magnitude is 66 N. What is the magnitude of the pulling force exerted by his wife?

    2. Relevant equations

    3. The attempt at a solution
  2. jcsd
  3. Dec 1, 2007 #2
    Any ideas on how to do this before we help?
  4. Dec 1, 2007 #3
    w = f * d (vectors)

    w of man = 66 * cos(58) * D

    w of woman = force * cos(34) * D

    w of woman = w of man

    66 * cos(58) * D = FORCE * cos(34) * D

    the distances cancel out and you are left with

    66 * cos(58)/cos(34) = answer
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