• Support PF! Buy your school textbooks, materials and every day products Here!

Magnitude of torque on a door

  • Thread starter trainumc
  • Start date
  • #1
4
0

Homework Statement



A uniform door weighs 53.0 N and is 0.9 m wide and 2.5 m high. What is the magnitude of the torque due to the door's own weight about a horizontal axis perpendicular to the door and passing through a corner?


Homework Equations




torque is equal to the perpendicular component of the force with the shortest distance between the roation axis and the point of application of the force

and

τ=r(Fsinθ)



The Attempt at a Solution




530*0.9*2.5*(sin90)


i really don't know where to begin, my teacher hasn't taught this yet, even though the webassign is due tomorrow. am i using the wrong formulas?
 

Answers and Replies

  • #2
LowlyPion
Homework Helper
3,090
4

Homework Statement



A uniform door weighs 53.0 N and is 0.9 m wide and 2.5 m high. What is the magnitude of the torque due to the door's own weight about a horizontal axis perpendicular to the door and passing through a corner?
Speaking generally you need to figure the distance of the Center of Mass as the point that you would have its weight act through relative to the desired axis of rotation.
 

Related Threads for: Magnitude of torque on a door

  • Last Post
Replies
11
Views
7K
  • Last Post
2
Replies
30
Views
5K
  • Last Post
Replies
2
Views
805
  • Last Post
Replies
1
Views
7K
Replies
0
Views
3K
  • Last Post
Replies
1
Views
5K
Replies
4
Views
19K
Replies
3
Views
20K
Top