Magnitudes of the largest and smallest force?

  • Thread starter Fittler
  • Start date
  • #26
for a) i see how the applied force would be against the force of gravity acting down the ramp and the force of friction acting against the force of gravity. for part b) i dont quite see how to recalculate the normal force, isnt Fn=mgcos45? i would then get the same results for the normal force unless mass, gravity or angle would change. my thinking is that the because it is the smallest amount needed you set the force of gravity against the box going down the ramp to 0, and end up with Fnet=0. Fnet=Fa-Ff, Fa=Ff. therefore the Fa=119.39
 

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