A man is running at speed [tex]c[/tex] (much less than the speed of light) to catch a bus already at a stop. At [tex]t=0[/tex], when he is a distance [tex]b[/tex] from the door to the bus, the bus starts moving with the positive acceleration [tex]a[/tex]. Use a coordinate system with [tex]x=0[/tex] at the door of the stopped bus i have two questions What is [tex]x[/tex]man[tex](t)[/tex], the position of the man as a function of time? Answer symbolically in terms of the variables [tex]b[/tex], [tex]c[/tex] , and [tex]t[/tex] . [tex]x[/tex]man[tex](t)[/tex] = _____________ (picture of the man and the bus is also included) because the man's speed is constant, i used the formula x(t) = x(0) + vt so.... [tex]x[/tex]man[tex](t)[/tex] =0+ct is that correct?