- #1

CellCoree

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A man is running at speed [tex]c[/tex] (much less than the speed of light) to catch a bus already at a stop. At [tex]t=0[/tex], when he is a distance [tex]b[/tex] from the door to the bus, the bus starts moving with the positive acceleration [tex]a[/tex].

Use a coordinate system with [tex]x=0[/tex] at the door of the stopped bus

i have two questions

What is [tex]x[/tex]man[tex](t)[/tex], the position of the man as a function of time? Answer symbolically in terms of the variables [tex]b[/tex], [tex]c[/tex] , and [tex]t[/tex] .

[tex]x[/tex]man[tex](t)[/tex] = _____________

(picture of the man and the bus is also included)

because the man's speed is constant, i used the formula

x(t) = x(0) + vt

so...

[tex]x[/tex]man[tex](t)[/tex] =0+ct

is that correct?

Use a coordinate system with [tex]x=0[/tex] at the door of the stopped bus

i have two questions

What is [tex]x[/tex]man[tex](t)[/tex], the position of the man as a function of time? Answer symbolically in terms of the variables [tex]b[/tex], [tex]c[/tex] , and [tex]t[/tex] .

[tex]x[/tex]man[tex](t)[/tex] = _____________

(picture of the man and the bus is also included)

because the man's speed is constant, i used the formula

x(t) = x(0) + vt

so...

[tex]x[/tex]man[tex](t)[/tex] =0+ct

is that correct?