Force Of Man On Elevator 1. The problem statement, all variables and given/known data An 65- kg man stands in an elevator. What force does he exert on the floor of the elevator under the following conditions? The elevator is stationary. Answer:637.65N The elevator accelerates upward at 2.3 m/s2. Answer:787.15N The elevator rises with constant velocity of 3.1 m/s. While going up, the elevator accelerates downward at 1.7 m/s2. Answer:527.15N The elevator goes down with constant velocity of 6.3 m/s. 2. Relevant equations EF=0 3. The attempt at a solution so far i have the ones where i allready have the acceleration but i don'tknow how to do the ones with velocity because i don't have a t(time) i thought maybe i could do the same and multiply 3.1m/s*65kg which is 201.5 and then use the formula EF=0 so EF=0=-201.5-637.65 which equals 839.15 but this was wrong, could you just give me an idea on how to get started and help would be greatly appreciated.