1. The problem statement, all variables and given/known data The figure shows a schematic drawing of an open ended well-type manometer. Attached to one end of the manometer tube is a well (a reservoir with a higher crossectional area compared to that of the tube). The manometer is filled with a fluid with an SG = 2.95. The manometer tube has a diameter of 5mm and the well is cylindrical with a diameter of 50mm. Initially, with the pressure on both sides of the manometer is atmospheric. The fluid level is consequently the same on both sides of the manometer. A gauge pressure of 2.1 psi is applied to the well side of the manometer. a) Calculate the difference in height of the fluid levels on each side of the manometer. b) Calculate the amount by which the fluid level on the well side is depressed. Calculate the amount by which the fluid level on the low pressure side rises. 2. Relevant equations ΔP = ρgh 3. The attempt at a solution h = ΔP/ρg h = 2.1 psi to pas / 2950 kg/m^3 * 9.81 2.1 psi to pas = 14478.99 Pa So, h = 14478.99/2950*9.81 a) h = 0.5 meaning the difference in height is 0.5m? b) Not sure what exactly the answer requires. Does it require the height in respect to an algebraic representation of the height of the water initially? Cheers.