Manometer U Tube

  • Thread starter tsslaporte
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  • #1
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Homework Statement

ZJYtq.png


The U-tube in the figure is sealed at both ends. It contains a gas in A, another gas in B, and mercury in C. The heights of the mercury in the two arms are as shown. The density of mercury is 13.6 g/cm3. If the pressure in A is 1 × 10^4 dyn/cm2, the pressure in B is


The attempt at a solution

4-7 = 3CM

0.03m * 9.81 * 13600 kg/m^3 which = 4000 Pa which converts to 4x10^4 dyn/cm^2

But the answer given was 5x10^4 dyn/cm^2


I am not sure what I am doing wrong?


Edit: 4x10E4 is the pressure difference. So I have to add A which is 1x10E4 and that gives B = 5x10E4.

Could someone explain why I add A?
 
Last edited:

Answers and Replies

  • #2
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One way to think about this problem is to calculate the pressure at the bottom of the U-tube. Look at the left U-tube column the pressure at the bottom is Pb+ hb*density*g that will equal the right U-tube Pa+ha*density*g

It is easy to see why you must add Pa if you are measuring the pressures at the bottom of the U-tube
 

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