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Manufacture of nitric acid

  1. Feb 24, 2005 #1

    k3l

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    from a series of reactions
    i got the formula which produces [tex]HNO_3[/tex]... the "result" formula is:
    [tex]4N_2_(_g_) + 6H_2_(_g_) + 8O_2_(_g_) -> 4HNO_3_(_a_q_) + 4H_2O_(_l_)[/tex]

    The question asks to find the weight of nitrogen,
    and the Volume of nitrogen (at STP) required to produce 5.00 kg pure nitric acid.

    what i want to know is what does it mean by the weight of nitrogen?

    thx
     
    Last edited: Feb 24, 2005
  2. jcsd
  3. Feb 24, 2005 #2

    Borek

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    Staff: Mentor

    Literally - weight of the nitrogen used. I suppose if it was a solid you will have no problems? So do it exactly the same way as if [tex]N_2[/tex] was solid.

    And don't forget that 1 mole of gas at STP has volume 22.4 l.

    Best,
    Borek
     
    Last edited by a moderator: Aug 13, 2013
  4. Feb 24, 2005 #3

    dextercioby

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    "Weight+chemistry=mass".Don't take it literally or as something axiomatic....


    Daniel.
     
  5. Feb 24, 2005 #4

    Borek

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    Now that you pointed at, it is obvious :blushing:

    The funny thing is I will never mix these things in Polish :smile:

    Best,
    Borek
     
    Last edited by a moderator: Aug 13, 2013
  6. Feb 24, 2005 #5

    dextercioby

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    In physics "weight" has other sense.Chemists are making their own rules.

    Daniel.
     
  7. Mar 3, 2005 #6
    That "formula" may describe the overall ratio of the elements involved, but it's NOT how HNO3 is made. Industrially, it's made by the catalytic oxidation of N2 to nitrogen oxides, which are dissolved in H2O to produce a mixture of HNO3/HNO2. The HNO2 is then oxidized to HNO3 with O2 from air. In the lab, HNO3 is made by heating a nitrate with H2SO4 and distilling off the vapor. But, you DON'T NEED the reaction formula to answer that question! You just need to calculate the number of moles of N in 5 kg of HNO3. Half that number will be the moles of N2 needed, and the volume is found by V = n*R*T/P
     
  8. Mar 8, 2005 #7
    isnt the volume occupied by 1 mole of gas: 24dm3 at 298K, and 22.4 at 293K?
     
  9. Mar 8, 2005 #8
    Listen to pack_rat2. You don't need the overall reaction because the only source of nitrogen in nitric acid is atmospheric nitrogen, or N2. 1 mole of nitric acid is made by half a mole of nitrogen.

    Weight of nitrogen = 0.556 kg
    Volume of nitrogen = 889 litres
     
    Last edited: Mar 8, 2005
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