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- Thread starter joeblow
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I can't see it by just looking at it, but I did manage to prove it by inserting [tex]z=re^{i\phi}[/tex], then finding x and y-components of the expression f(z) in terms of [tex]\cos(\phi)[/tex] and [tex]\sin(\phi)[/tex]. Then I used the relationship [tex]cos^2 + sin^2 = 1[/tex] to find an expression among x and y, which turned out to be the equation for an ellipse, as long as r>=1.

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