Mass and atoms

1. Sep 27, 2016

Kpgabriel

1. The problem statement, all variables and given/known data
Lead has a mass of 11.35 g per cubic centimeter of volume, and the mass of one of its atoms is 3.439×10-25 kg. If the atoms are spherical and tightly packed, what is the volume of an individual atom? ( m3)

2. Relevant equations
conversions

3. The attempt at a solution
For this problem I converted the 11.35 g/cm ^3 into 11350 g/m^3 and then converted the atom from 3.439*10^-25 kg into 3.439*10^-22 g. Then I divided it by the 11350 to get m^3 and the result was 3.03*10^-26 but it appears to be wrong.

2. Sep 27, 2016

Bystander

3. Sep 27, 2016

PeroK

How many $cm$ are there in a $m$?

Last edited: Sep 27, 2016
4. Sep 27, 2016

Kpgabriel

100 so it would be cubed to get m^3 and it would be 3.03*10^-29 which is the right answer

5. Sep 27, 2016

Mathijsgri

If 11,35 grams fit into 1 cm3 then 3.439×10-22 g will fitt into
3.439×10-22g/ 11.35= 3.03 cm3

6. Sep 27, 2016

Mathijsgri

* 3.03*10-23 cm3

7. Sep 27, 2016

Kpgabriel

But you're looking for m^3

8. Sep 27, 2016

Mathijsgri

1m3= 1.000.000cm3
? = 3.03*10 - 23cm3

9. Sep 27, 2016

PeroK

Are you helping him now?

10. Sep 27, 2016

Mathijsgri

'crosswise multiplication table' i don't know if it is an english term, i translated it literally from dutch.

11. Sep 27, 2016

Kpgabriel

Right. so it would be 11.35 g/cm^3 * 1000000cm^3/1 m^3 to give 11350000 g/m^3 which you divide into 3.439*10^-22 g

12. Sep 27, 2016

Kpgabriel

I just call it a conversion

13. Sep 27, 2016

Mathijsgri

keep in mind that 1 cm3 is not equalle to 1.000.000 m3

14. Sep 27, 2016

PeroK

I don't think you're helping here. The OP has got the correct answer. Leaving aside the question of the basic volume of a sphere as opposed to the volume it occupies in a 3D array.

15. Sep 27, 2016

PeroK

16. Sep 27, 2016

Mathijsgri

you are right i made a typo in my calculator, sorry for that.

17. Sep 27, 2016

Kpgabriel

Yes it was a test question I got wrong so I was trying to find the correct method to the answer