For lead N=210 Z=82 Pb (atomic mass = 209.984163 u) obtain each of the following:
(a) The mass defect in atomic mass units
(b) the binding energy (in MeV)
(c) the binding energy per nucleon (in MeV)
The Attempt at a Solution
a) 82 x 1.6726e-27 kg + 128 x 1.6749e-27 kg= 3.515e-25 kg
3.515e-25kg x 1u/1.6605e-27= 211.708
211.708-209.984163= 1.72u but it says my answer is wrong.