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Mass Defect

  1. Mar 3, 2007 #1
    1. The problem statement, all variables and given/known data

    For lead N=210 Z=82 Pb (atomic mass = 209.984163 u) obtain each of the following:
    (a) The mass defect in atomic mass units
    (b) the binding energy (in MeV)
    (c) the binding energy per nucleon (in MeV)

    2. Relevant equations

    3. The attempt at a solution

    a) 82 x 1.6726e-27 kg + 128 x 1.6749e-27 kg= 3.515e-25 kg

    3.515e-25kg x 1u/1.6605e-27= 211.708

    211.708-209.984163= 1.72u but it says my answer is wrong.
  2. jcsd
  3. Mar 3, 2007 #2
    Nevermind. I forgot to initially subtract the mass of the 82 electrons from the mass of entire atom.
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