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Mass flow rate

  1. Dec 6, 2008 #1
    1. The problem statement, all variables and given/known data
    see attachment

    2. Relevant equations
    mass flow rate =roe*dV/dt

    3. The attempt at a solution
    the velocity at point c is 50m/s and the area of the opening is 0.04m^2. (50m/s)(0.04m^2)(1000kg/m^3)=2000Kg/s

    Attached Files:

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  2. jcsd
  3. Dec 8, 2008 #2
    Do you think these questions sometimes give you extra information in order for you to show that you know how to sort out the essential from the not useful?
    At point B the pipe is wider than at C.
    At B will the water be flowing faster, slower, or the same speed as a point C ?
    Obviously the same amount of water must pass point B and point C.
    So what can we say about the mass flow at B?
  4. Dec 8, 2008 #3


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    Looks correct to me.

  5. Dec 8, 2008 #4
    Yes he's right, but the question gives a lot of unnecessary detail and I was trying to see if he was misled by it.
  6. Dec 8, 2008 #5
    I was a little mislead by the simplicity of the problem. Since the 6th grade, I've known some problems give more information than needed.
  7. Dec 9, 2008 #6


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    Typically when students give the correct answer it implies that they were not mislead by it! :wink:

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