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## Homework Statement

Water enters a kidney through a tube at 10 mL/min. It exits through a 6-mm-diameter tube at 20 mm/s.What is the rate of change of mass of water in the kidney?

## Homework Equations

m=vpa

q=va

After conversions to meters

V=.02

Q=.000167

A=(pi/4)*.006^2 = .0000282

## The Attempt at a Solution

dm/dt-Qp+VAp=0

dm/dt-(.000167)(999.1)+(.0000282)(.02)(999.1)=0

dm/dt=.165 kg/s

Needless to say, thats not the right answer, but I can't figure out where I went wrong.