Water enters a kidney through a tube at 10 mL/min. It exits through a 6-mm-diameter tube at 20 mm/s.What is the rate of change of mass of water in the kidney?
After conversions to meters
A=(pi/4)*.006^2 = .0000282
The Attempt at a Solution
Needless to say, thats not the right answer, but I can't figure out where I went wrong.