Hello, If I get 2.0830 grams of tobacco and add 1 gram of barium hyrdoxide to it. Mix it in 100 mL of chloroform:toluene mixture, I essential have a 100 mL solution right? Now I take a 25 mL aliquote from that? what will be the mass in grams of tobaco in that 25 mL sample? I thought simply 2.0830 x (25ml/100 mL) would do but my T.A. asked me to recalculate that because I did it wrong. Thanks.