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Mass of Anhydrous Compound

  1. Oct 5, 2009 #1
    The problem statement, all variables and given/known data
    What is the mass of the anhydrous compound in [tex]Cu(NO_{3})_{2} * 2.5 H_{2}O[/tex]
    , in other words, the [tex]Cu(NO_{3})_{2}[/tex], if 4.875g of the hydrated compound is used?


    The attempt at a solution
    What I did was find the formula mass of [tex]Cu(NO_{3})_{2}[/tex] which turned out to be 187.57g
    Cu= 1 * 63.55 = 63.55
    N= 2 * 14.01 = 28.02
    O = 6 * 16.00 = 96.00

    The formula mass of the water is 45.05g
    H= 2.5(1.01 * 2) = 5.05g
    O= 2.5(16.00 * 1) = 40g

    From here I set up a ratio:
    4.875/232.62 = x/187.57
    x = 3.931g of [tex]Cu(NO_{3})_{2}[/tex]

    Is this right?
     
  2. jcsd
  3. Oct 6, 2009 #2

    symbolipoint

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    The method looks good.
     
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