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Mass of water in a cloud

  1. Jan 19, 2008 #1
    [SOLVED] Mass of water in a cloud

    1. The problem statement, all variables and given/known data
    One cubic centimeter of a cumulus contains 220 water drops, which have a typical radius of 10 μm. (a) How many cubic meters of water are in a cylindrical cumulus cloud of height 3.0 km and radius 1.0 km? (b) How many 1-liter pop bottles would that water fill? (c) Water has a density of 1000 kg/m^3. How much mass does the water in the cloud have?


    2. Relevant equations



    3. The attempt at a solution
    OK here is what I have so far I know I'm almost there I'm just making some simple mistake somewhere along the line.

    First 1 cm^3 of a cloud = (220 drops/cm^3) wich equals 220*10^6 drops/m^3

    10 microns = 10*10^-6m = radius of a drop. So the density of a drop = 4.188790205E-5m

    Volume of the cloud = (Pi)r^2*h = (Pi)(1000m)^2(3000m) = 942477961m (? messing up here?) But this isn't the answer to (A)?

    (B) is just a conversion of (A) so..

    (C) Well i guess I only got to (A)


    Any help of what I'm doing wrong or how I should be going about this would be appreciated. Thanks,
     
  2. jcsd
  3. Jan 19, 2008 #2

    Kurdt

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    You've calculated the volume of the cloud for a) but what they want is the volume of water in the cloud in cubic meters. What you were doing before calculating the clouds volume was along the right lines to help get the final answer.
     
  4. Jan 19, 2008 #3
    When I cube the answer for (A) it still comes up wrong
     
  5. Jan 19, 2008 #4
    To continue: The #drops = ((Whatever A should be)(220*10^(6) drop/m^3) = ?

    So mass of cloud = (# drops)(4/3 (Pi)(10*10^(-6)m^3)) right? Don't know where I'm going wrong with (A).
     
  6. Jan 19, 2008 #5

    Kurdt

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    You've calculated the volume of the cloud. Now you need to know the volume of water in the cloud. Since you know the volume of each drop (because you have the radius and assuming they're spheres) and you know how many drops are in a cubic centimeter you can work out the volume of water in the whole cloud.
     
  7. Jan 19, 2008 #6
    I added it together and still ended up getting it wrong so I'm not sure what I'm doing wrong :( Its frustrating though.
     
  8. Jan 19, 2008 #7

    hage567

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    The volume of the cloud and the volume of the water are not the same. I think that's where you are getting confused.

    I think you are getting ahead of yourself here.
    The number of drops is part of determining the answer to (a). First, find the volume of the cloud. You've done this in your first post, but I think you're answer is off by a factor of ten. Double check it. Once you have this, you can find the total number of drops in the cloud. The number of drops will be the volume of the cloud * the number of drops/m^3.

    This equation does not give you mass, check the units. This gives you the volume of water in the cloud. Which is what you are trying to calculate for (a).

    Don't worry about mass and density yet, that's for part (c).
     
  9. Jan 19, 2008 #8
    Well I figured it out finally,

    (a)8.685E3m^3

    (b)8685000bottles

    (c)8685000kg

    Thanks for the help!
     
  10. Jan 19, 2008 #9

    hage567

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    Good work! :smile:
     
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