Mass of water molecule

1. Jun 9, 2005

Kamataat

Is there any way to find the mass of a water molecule when only Avogadro's number is given?

Thanks!

- Kamataat

2. Jun 9, 2005

Smith4046

Think I got it!

The mass of one mole of water = 18 grams.

18gms/mole divided by 6.02x10^23 molecules/mole should work, if my chemistry isn't too rusty. The mole units will cancel each other, leaving you with units of gms/molecule.

Should get something like 3x10^-23 gm/molecule. Actually a little less, since I rounded all numbers off.

Please correct me (anyone) if I am incorrect!

Good luck.

Steve

3. Jun 9, 2005

Kamataat

Yeah, that's how I'd do it, but I was asking because of the stupid excercise book. It gives all sorts of extra info in the back, in case it's required to solve a problem, but it doesn't give any molar masses. So I thought that maybe there's a clever way to solve this w/o the molar mass.

All I know is Avogadro's number, the definition of a mole (# of atoms in 0.012kg of $C^{12}$) and Clapeyron's equation.

Thanks anyway!

- Kamataat

4. Jun 9, 2005

moose

The easiest way to figure out the molar mass is to look at a pereodic table of elements.....Off the top of my head, two hydrogen(1.01) and one oxygen(16), you just add those and get the molar mass.

Am I missing something....?

5. Jun 9, 2005

bross7

No, that definately should be what you do. Most problems just don't give molar masses for things like water, carbon dioxide, etc. in some chemistry books because the value is given so many times over that it becomes one of those redundant things.

Given only avogadro's number, you definately need to have the molar mass to find the number of molecules.

6. Jun 10, 2005

whozum

The average molar mass for an element is given on any periodic table, and certain isotopes can be looked up. Water is 2 hydrogens (1.01 each) and one oxygen (16) which gives 16 + 2(1.01) = 18.02 g/mol.

$$\left(\frac{18.02 g}{1 mol}\right) \left(\frac{1 mol}{6.02 \times 10^{23} molecules}\right) = \left(\frac{ x grams}{ 1 molecule }\right)$$

7. Jun 10, 2005

theCandyman

Smith basically used this then multiplied by one mole then divided by one mole.

8. Jun 10, 2005

Kamataat

Thanks everyone for making this clear for me!!!

- Kamataat