- #1

- 11

- 0

m=5 kg

vo=40 m/s

θ=30°

S=the distance you are looking for

Coefficient of friction (μ) = 0.15

Work energy theorem=mg(hf-ho) + 1/2 m (vf^2-vo^2) +fs

Attempt:

i set up the work energy theorem and simplified it down to "work=mghf-1/2mvo^s+μ

mgs" and solved for s

and then i used "work= -mgho + 1/2mvf^s +μ

mgs to solve for vf

i honestly had no clue what to do for the third part of this problem

I dont think my answers are right bc i got 0.598 m fr the first part and 2.23 m/s fr the second part...and i couldnt figure out the third part

Help would be appreciated. Thank u very much to all!