- #1
scuddman
- 6
- 0
A crate of mass M is placed on a frictionless inclined plane of Angle theta.
Determine the acceleration after the crate is released.
|\
|..\o crate of mass m
|...\
|___b\ angle b which is theta.
I know how to do this problem if I set up the axis a certain way. If I slant the axis so that the acceleration is in the X direction, then the problem is easy:
F = MA
F in the x direction = MGsin(theta) = MA in the x direction
F in the y direction = N (normal force) -MGcos(theta) = 0
MA = MGsin(theta)
A = Gsin(theta)
However, I'm now asked to do the problem except with the axis the normal way, and while the free body diagram looks the same, I don't know how to precede from there because the axis are different.
.../Normal force
../
.o object
.|
.|
mg
Here is the free body diagram..
F in the Y direction: Ncos(theta) - mg ?? something like this?
F in the X direction: N sin(theta)
F = ma
Ncos(theta) - mg = MA in the y direction <- y component of acc.
Nsin(theta) = MA in the X direction <- x component of acc.
Something like that?
Determine the acceleration after the crate is released.
|\
|..\o crate of mass m
|...\
|___b\ angle b which is theta.
I know how to do this problem if I set up the axis a certain way. If I slant the axis so that the acceleration is in the X direction, then the problem is easy:
F = MA
F in the x direction = MGsin(theta) = MA in the x direction
F in the y direction = N (normal force) -MGcos(theta) = 0
MA = MGsin(theta)
A = Gsin(theta)
However, I'm now asked to do the problem except with the axis the normal way, and while the free body diagram looks the same, I don't know how to precede from there because the axis are different.
.../Normal force
../
.o object
.|
.|
mg
Here is the free body diagram..
F in the Y direction: Ncos(theta) - mg ?? something like this?
F in the X direction: N sin(theta)
F = ma
Ncos(theta) - mg = MA in the y direction <- y component of acc.
Nsin(theta) = MA in the X direction <- x component of acc.
Something like that?