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Mass on string

  1. Nov 22, 2009 #1
    1. The problem statement, all variables and given/known data

    8. A mass m1 suspended on a string of length L is released from rest with, the string horizontal, as shown in the diagram. At the lowest point in its swing, m1 collides elastically with a stationary mass m2 = 2m1 suspended on a string of length L. Calculate the maximum angle that the string suspending m2 makes with the vertical following the initial collision. noite the picture

    2. Relevant equations



    3. The attempt at a solution

    m1gL = .5m1v1o2..v1o = (2gL)1/2

    m1v1o = m1v1 + m2v2 = m1v1 + 2m1v2..v2 = ((2gL)1/2-v1)/2

    .5m2v22 = m2gh.... h = L(L-cosQ)

    .5(((2gL)1/2-v1)/2)2 = gL(L-cosQ)

    Q = arccos[L - ((((2gL)1/2-v1)/2)2)/2gL]

    is this correct so far... i will then take the derivative of Q interms of v1 I believe.... if so, is taking the derivative of an inverse function the same as the other trig functions
     

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