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Mass-spring system; Hill equation

  1. Dec 8, 2008 #1
    When trying to solve a problem I arrive at the following equation of motion / Hill equation:

    [tex]\frac{d^{2}y}{dx^2} + \frac{4 k_0}{m w^2} cos(2x)y = 0[/tex]

    There exists a value x_0 such that for all x>x_0 the motion is stable.

    I actually don't know what is meant by this 'stability'. Can someone help, please?

    Thanks, Drokz
     
  2. jcsd
  3. Dec 8, 2008 #2

    marcusl

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    I've usually seen Hill's equation with omega^2, not omega^(-2). Is this a typo?
     
  4. Dec 9, 2008 #3
    I don't think it is a typo. Omega is just a constant here, I think.
     
  5. Dec 9, 2008 #4

    marcusl

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    Ok. Solutions are products of exponential terms and periodic functions, so your stability condition is needed to keep the exponential parts of the solutions bounded. Do you have access to a reference on Mathieu functions like Whittaker and Watson, or Erdelyi's Higher Transcendental Functions? The latter one has a clear discussion of the stable and unstable solution regions (p. 101 vol. 3).
     
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