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*A mass is suspended from a spring balance in a ship sailing along the equator with a speed v.*

(a) Show that the scale reading will be very close to wo = (1 ± 2ωv/g), where ω is the angular

speed of Earth, and wo is the weight of the mass with the ship at rest.

(b) Explain the ± sign.(a) Show that the scale reading will be very close to wo = (1 ± 2ωv/g), where ω is the angular

speed of Earth, and wo is the weight of the mass with the ship at rest.

(b) Explain the ± sign

I have wrapped my head around the question but am having trouble coming up with the given equation.

-The weight of the mass at rest will be equal to mg- the centripetal force of the rotating earth.

-The weight of the mass when the ship is sailing will be close to wo, but differ depending of the direction the ship is sailing, hence the ±.

-As this is the case I recognize that the velocity when calculating the centripetal force on the mass will be ω±v/r.

*What I do not see is how 1 came into 1 ± 2ωv/g, nor where the mass or radius went*

Thank you for any help,

Lucas