1. Limited time only! Sign up for a free 30min personal tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Homework Help: Massless particle revolving in a circle

  1. Oct 26, 2005 #1
    Given: A massless particle revolving in a circle with a rotational velocity = (2+sin(a))
    To Find: Y-axis acceleration
    Method #1 (from rotational acceleration)
    Y-axis acceleration = (2+sin(a))(cos(a))^2
    Method #2 (from Y-axis velocity)
    Y-axis acceleration = (2+sin(a))(cos(a))^2-(sin(a))(2+sin(a))

    Which Y-axis acceleration is correct and why?

    Can someone explain this?
  2. jcsd
  3. Oct 26, 2005 #2


    User Avatar
    Science Advisor

    What does this mean? Is a an angle? If so what angle?
    And what do you mean by "y-axis" acceleration? Are we to assume that the circle is in the xy-plane and you are looking for the y-component of acceleration?
  4. Oct 26, 2005 #3
    You tell me. I have no clue what they are asking. :cry:
  5. Oct 26, 2005 #4


    User Avatar
    Staff Emeritus
    Science Advisor
    Gold Member

    Post the problem EXACTLY as it appears in your text/homework. Attach any pictures that come with the problem (or describe them).
Share this great discussion with others via Reddit, Google+, Twitter, or Facebook