Massless particle revolving in a circle

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  • #1
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Given: A massless particle revolving in a circle with a rotational velocity = (2+sin(a))
To Find: Y-axis acceleration
Method #1 (from rotational acceleration)
Y-axis acceleration = (2+sin(a))(cos(a))^2
Method #2 (from Y-axis velocity)
Y-axis acceleration = (2+sin(a))(cos(a))^2-(sin(a))(2+sin(a))

Which Y-axis acceleration is correct and why?

Can someone explain this?
 

Answers and Replies

  • #2
HallsofIvy
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rotational velocity = (2+sin(a))
What does this mean? Is a an angle? If so what angle?
And what do you mean by "y-axis" acceleration? Are we to assume that the circle is in the xy-plane and you are looking for the y-component of acceleration?
 
  • #3
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HallsofIvy said:
What does this mean? Is a an angle? If so what angle?
And what do you mean by "y-axis" acceleration? Are we to assume that the circle is in the xy-plane and you are looking for the y-component of acceleration?
You tell me. I have no clue what they are asking. :cry:
 
  • #4
Gokul43201
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Post the problem EXACTLY as it appears in your text/homework. Attach any pictures that come with the problem (or describe them).
 

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