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Material shear and normal stress question

  1. Oct 9, 2012 #1
    1. The problem statement, all variables and given/known data

    Everything needed is written in the question ( Open the attached image )
    Nyhow the required is to find the value of P.


    2. Relevant equations

    [tex] Shear stress = \frac{ \Delta V }{\Delta A} [/tex] eq 1
    [tex] normal stress = \frac{ \Delta N }{\Delta A} [/tex] eq 2


    3. The attempt at a solution


    For the coned part,

    I know that

    [tex] r = (h + 25)/1000 meters [/tex] so is substute in

    [tex] A = 2 \pi r h [/tex] to get

    [tex] A = 2 \pi \frac{(h^2 + 25h)}{1000} [/tex] therefore taking the derivative DA/DH give

    [tex] dA = \frac{4 \pi h + 50 \pi}{1000} .dh [/tex] substute to derivative of eq 2 and then integrate wiith respect to h for the boundries 0 < h < 50*10^-3 m and then multiplying by sin (45) to get sum of vertical force.

    For the cylindrical part,

    Just multiply A = 2*pie*r*30*10^(-3) to shear stress to get the force.
    suming up the two force should equal P. however i got it wrong :/ !

    So any ideas of how to solve this beast ??
     

    Attached Files:

  2. jcsd
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