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Math 31 Rates of change

  1. Apr 13, 2005 #1
    I need help with the question: The heighth of an equilateral triangle is increasing at a rate of 3cm/min. How fast is the area changing when h is 5cm?
  2. jcsd
  3. Apr 13, 2005 #2
    The area of a triangle is A= 1/2*bh

    You know dh/dt = 3cm/min

    Try manipulating the above equations to an appropriate form where you can find the area as a function of height, and inhernetly its rate of change.
  4. Apr 14, 2005 #3


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    Write the equation, which whozum gave you, A= (1/2)bh, Use a relation between b and h that is true for all equilateral triangles (divide the triangle into two right triangles and use the Pythagorean theorem) to write A as a function of h only.
    Finally, differentiate with respect to t to get a relation between dA/dt and dh/dt.
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