Math Challenge Problem: Finding angular velocity(kinimatics, 3D Geometry, calc I)

  • #1
169
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Some of my friends, upon finding out that I'd joined these forums, decided to give me a math challenge problem they thought couldn't be solved. Does everyone get the same answer? It goes as follows:

A knight jumps on a chess board (assume it makes a legal move) from point A to point B. Relative to an observing point O, what is the rate of change of angle of the chess piece as a function of time?

Let/Assume:
The piece makes a legal move
The piece is a knight
s (given) : the scale of the chess board. One space has width and height S
C = current position of the piece as a function of time
P = the current position of the piece projected down onto the plane of the chess board
R is a reference point which is always directly right of the center point
[itex]\theta[/itex] (given) is the launch angle
g (constant) is acceleration due to gravity
Coordinate system is defined as the chess board itself, with the origin in one of the corners.
Let theta be the launch angle of the piece.
After launch the piece is solely under the influence of gravity
Find:
A function for the measure of the angle AOP, n (angle in the plane of the board)
A function for the measure of the angle POC, a (accention)
Time rate of change of n, n'
Time rate of change of a, a'
You have access to the aTan2 function, which properly returns the angle between the reference (+X axis) and any point giving an ordered pair IE: aTan2(-2,-1) => 210degrees
Strategy(with calculus)
-I)describe the distance between points A and B, in the plane of the board(d)
-II)derive a function for the vertical component of velocity of the piece, a function of theta, launch velocity, and time
-III)Integrate said function to get a h as a function of time, launch velocity, and launch angle
-IV)Use the definition of velocity to generate a function for s of t and d
-V)Solve the system of eqs from III and IV for initial velocity
-VI)Define the magnitude ||OA|| and ||OB||, rI and rF
-VII)Define the angle between the reference(+X axis) , and OA, OB
-VIII)Write R(t,RI,RF), giving the length of OP at any time
-IX)Take the derivative dR/dt
-X)Realize n is given by ROA plus angle AOP; AOP is determined by creating a right triangle with AO and the component AP perpendicular to AO, and adding their associated rate of change times time.
-XI)Take the derivative with respect to time of n to get n', and one of the answers. Remember your chain rule!
-XII)go back to IX, and realize that a (COP) can be determined from the triangle COP. h = ||CP||, r = ||OP||.
-XIII)once you have a, take the derivative to find the time rate of change of a, a'
I
-I)describe the distance between points A and B, in the plane of the board(d)
knights move up 1 over 2, or up 2 over 1, either way, the distance between A and B is:
d = S*[itex]\sqrt{1^2+2^2}[/itex]
d = S[itex]\sqrt{5}[/itex]
II
-II)derive a function for the vertical component of velocity of the piece, a function of theta, launch velocity, and time
accel=g
Vh=h'=gt+C=gt+V0Sin([itex]\theta[/itex])
III
-III)Integrate said function to get a h as a function of time, launch velocity, and launch angle
h=gt2+V0Sin([itex]\theta[/itex])t+0
(assume time zero is launch)
IV
-IV)Use the definition of velocity to generate a function for s of t and d
distance=rate*time
d/([itex]\Delta[/itex]t) = cos([itex]\theta[/itex])V0
s= cos([itex]\theta[/itex])V0[itex]\Delta[/itex]t
V
-V)Solve the system of equations from III and IV for initial velocity
h=gt2+V0Sin([itex]\theta[/itex])t
0=gt+V0Sin([itex]\theta[/itex])
-gV0 csc([itex]\theta[/itex]) = [itex]\Delta[/itex]t
...
I'll finish the rest of this later...
Answer
View attachment challengeProblem.zip
 
Last edited:

Answers and Replies

  • #2
459
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A knight jumps on a chess board (assume it makes a legal move) from point A to point B. Relative to an observing point O, what is the rate of change of angle of the chess piece as a function of time?
Seems to me it could be anything you want. Nothing in the problem statement tells us how fast the knight moves. It could take a millisecond to get from A to B, or a century.

What am I missing?
 
  • #3
1,065
53
pmsrw3: I think reason why you think you are missing something is because there is no hard coded distance...every square is S x S ; other than that, it is just a projectile shooting from A to B....isn't it?
 
  • #4
169
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I knew I forgot something when I posted. Assume you have the width of a tile, launch angle, and acceleration of gravity, as well as the coordinates of O, A, and B. This is indeed a projectile motion problem.
 

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