1. The problem statement, all variables and given/known data 2 moles of an ideal gas, P1 = 10 atm V1 = 5L, are taken reversibly in a clockwise direction around a circular path given by (V-10)^2 + (P-10)^2 = 25. All I have left to solve for is the minimum temperature. 2. Relevant equations PV = nRT 3. The attempt at a solution I found T1 = PV/nR = (10atm * 5L) / (2 moles * .08206) = 304.66K From the equation I found out that the center of the circle is (V, P) = (10,10) with a Radius of 5. From there I broke the circle up into 4 different sections starting at (5,10) and going clockwise. I found the max by saying that P = V and between (10, 15) and (15,10), (V-10)^2 = (P-10)^2 = 12.5 P-10 = 3.536 Vmax = Pmax = 13.536 and Vmin = Pmin = 6.464 PV = nRT Tmax = (13.536^2)/(2 moles * .08206) = 1116K (correct answer) Tmin = (6.464^2)/(2moles * .08206) = 255K (Answer:Tmin = 225K) Did I miscalculate where PV is a minimum between the section of (10,5) and (5,10) of the circle?