- #1
m00npirate
- 50
- 0
I have been trying for the past hour or so to figure out the solution to this equation:
[tex] \sqrt{x} + 1 = 0[/tex]
but to no avail! Here's what i tried...
[tex] \sqrt{x} = -1 [/tex]
[tex]\sqrt{x} = i^4 [/tex]
[tex]x = \pm i^8 [/tex]
[tex]x = \pm 1[/tex]
But this is most obviously wrong. What did I do wrong and what is the real answer?
[tex] \sqrt{x} + 1 = 0[/tex]
but to no avail! Here's what i tried...
[tex] \sqrt{x} = -1 [/tex]
[tex]\sqrt{x} = i^4 [/tex]
[tex]x = \pm i^8 [/tex]
[tex]x = \pm 1[/tex]
But this is most obviously wrong. What did I do wrong and what is the real answer?