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Rewrite the expression in terms of the first power of the cosine:

cos^6 x

My guess would be that it would be cos(x)*cos(x)*cos(x)*cos(x)*cos(x)*cos(x)

I'm not sure if that is it, or any way to start the problem even

Please help me

edit :

cos^6(x)=cos^2(x)*cos^2(x)*cos^2(x)

=.5(1+cos2x)*.5(1+cos2x)*.5(1+cos2x)

then ???

?

cos^6 x

My guess would be that it would be cos(x)*cos(x)*cos(x)*cos(x)*cos(x)*cos(x)

I'm not sure if that is it, or any way to start the problem even

Please help me

edit :

cos^6(x)=cos^2(x)*cos^2(x)*cos^2(x)

=.5(1+cos2x)*.5(1+cos2x)*.5(1+cos2x)

then ???

?

Last edited: