Use a calculator to evaluate the following powers

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In summary, the powers that the person talked about are: 3^(14/10), 3^(141/100), 3^(1414/10000), 3^(14142/10000) and 3^(141421/100000). They found that 3^(1414213/1000000) is the value of 3^(sqrt of 2). They also found that 3^(14/10), 3^(141/100), 3^(1414/10000), 3^(14142/10000), and 3^(141421/100000) are all converging to 3^(sqrt of 2). The person is asking for help in understanding how to define 3
  • #1
jai6638
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Hey... requested my professor to give me a few questions to enable me to improve my skills... am having problems solving them however and was hoping that you could guys could help me:

Q1) Use a calculator to evaluate the following powers. Round the results to five decimal placeS. Each of these powers has a rational exponent. Explain how you can use these powers to define 3^( sqrt of 2 ) which has an irrational exponent.

3^(14/10) = 4.65554
3^(141/100)=4.70697
3^(1414/10000)= 4.72770
3^(14142/10000)= 4.72873
3^(141421/100000)= 4.72878
3^(1414213/1000000)= 4.72880


3^( sqrt of 2 ) = 4.728804

so basically the value of 3^(sqrt of 2 ) comes after 3^(1414213/1000000)... hence, you could find the log of 3^14/10 which is .6679697566, then probably do the following : 3^(.667..+.667...+.667...+.667.. +.667 +.667.. +.667).

EDIT: damn .. what i did above doesn't make sense.. I am soo confused.! i do know that i can somehow use logs by finding the log of one value and then adding the solution multiple times to find the value of 3^ ( sqrt of 2 )

EDIT 2: realized that i posted in wrong forum.. my bad.. shall post in general math forum...
 
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  • #2
Surely, this is not just an exercise in using a calculator! And this isn't a "word problem" so I'm not sure what you meant by that first sentence. The point of the exercise appears to me to be: You have already defined exponentials for any rational power by am/n= (am)1/n= [itex]^n\sqrt{a^m}[/itex].
Now, how do you define exponentials for irrational numbers? Every irrational number is the limit of some sequence of rational numbers- that's exactly what you are doing when you say, for example, pi= 3.1415926... 3, 3.1, 3.14, 3.141, 3.14159, 3.141592, 3.1415926,... is a sequence of rational numbers (because they are terminating decimals which could be written as a fraction exactly as you did [itex]\sqrt{2}[/itex])

DEFINING ax to be the limit of [itex]a^{r_n}[/itex] where rn is a sequence of numbers converging to x is just defining ax to be continuous.

You are right: "you could find the log of 3^14/10 which is .6679697566, then probably do the following : 3^(.667..+.667...+.667...+.667.. +.667 +.667.. +.667)."

doesn't make sense. Yes, 314/10 is, approximately, 0.66790696... but it makes no sense to talk about 3 to a sum of that. Are you confusing the exponent
14/10= 1.4 with the whole thing: 314/10?
 
  • #3
thanks much for your help.. appreciate it..
 

1. What does it mean to "evaluate" a power using a calculator?

Evaluating a power means using a calculator to find the numerical result of a mathematical expression written in the form of a power, where the base number is raised to a certain exponent.

2. How do I enter a power into a calculator?

Most calculators have a specific button or function for entering powers. This is often labeled as "xy" or "^". You can also use parentheses to indicate the exponent, such as entering "2(3)" for 23.

3. Can I use any calculator to evaluate powers?

Yes, as long as the calculator has a function for entering powers. This includes basic scientific calculators, graphing calculators, and online calculators.

4. What do I do if the calculator gives me an error when evaluating a power?

If the calculator gives you an error, it could mean that the power is too large or too small for the calculator to handle. Try using a different calculator or breaking the power down into smaller parts.

5. Can a calculator evaluate all types of powers?

Yes, a calculator can evaluate any type of power, including positive and negative exponents, fractional exponents, and powers with decimals. However, some calculators may have limitations on the size of the power it can handle.

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